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Handle filenames with spaces in hashfiles

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This commit is contained in:
Matt Nadareski
2023-03-30 10:59:56 -04:00
parent 6ee9edfe89
commit aa5cc76f8f
1 changed files with 4 additions and 5 deletions
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9
SabreTools.DatFiles/Formats/Hashfile.cs
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@@ -2,7 +2,6 @@
using System.Collections.Generic; using System.Collections.Generic;
using System.IO; using System.IO;
using System.Text; using System.Text;
using System.Text.RegularExpressions;
using SabreTools.Core; using SabreTools.Core;
using SabreTools.DatItems; using SabreTools.DatItems;
using SabreTools.DatItems.Formats; using SabreTools.DatItems.Formats;
@@ -44,20 +43,20 @@ namespace SabreTools.DatFiles.Formats
string line = sr.ReadLine(); string line = sr.ReadLine();
// Split the line and get the name and hash // Split the line and get the name and hash
string[] split = Regex.Replace(line, @"\s+", " ").Split(' '); string[] split = line.Split(' ');
string name = string.Empty; string name = string.Empty;
string hash = string.Empty; string hash = string.Empty;
// If we have CRC, then it's an SFV file and the name is first // If we have CRC, then it's an SFV file and the name is first
if (_hash.HasFlag(Hash.CRC)) if (_hash.HasFlag(Hash.CRC))
{ {
name = split[0].Replace("*", String.Empty); name = string.Join(" ", split[..^1]).Replace("*", String.Empty);
hash = split[1]; hash = split[^1];
} }
// Otherwise, the name is second // Otherwise, the name is second
else else
{ {
name = split[1].Replace("*", String.Empty); name = string.Join(" ", split[1..]).Replace("*", String.Empty);
hash = split[0]; hash = split[0];
} }